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voxel

@neauoire does the sender wait for all of the receivers to indicate that they're ready to receive? Do they have input buffers that are always writeable? I'm wondering what happens if multiple programs try to write send to a receiver at once, or if one receiver becomes 'unready to receive' during its execution

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Devine Lu Linvega replied to voxel

@voxel yeah it will wait, and events will be queued until it's ready to go through. I might have fun with more non-deterministic stuff in the future, but I haven't found a use for it yet, so it's all sequential atm.

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