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Ken Shirriff

@multioculate But why won't both capacitors end up at the average voltage: (V1 + V2 + Vcc)/2?

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multioculate

@kenshirriff the "upside down" p-FET only lets the charge in the donor transistor through, and chokes off before the clock voltage can start contributing. Here's a quick and ugly Falstad sketch I made on my phone:
tinyurl.com/28yhhbq4

You effectively get a constant 0.7V offset from the MOSFET threshold added to it because of my sloppy circuit, but I imagine the real one accounts for this at the input/output.

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