Gregory's Server@ruffni in real life a has a 4000+ various numbers, each in range from 1.0 to 3.0: 1.8, 2.6, 3.0, 3.0, 2.8, 1.0, 2.4, 1.2, 2.8, 1.0... and etc.
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3 comments
 @ruffni "memorize the result": you mean what I need add random numbers in array and substruct until I got result between 1.0 and 3.0? |
@toby3d so, since there are only 21 distinct numbers from 1.0 to 3.0 i'm guessing you don't mean *set*, since in maths this implies distinct elements.
if you want a list of say x=3 elements to average 2.35. this means you want r[0]+r[1]+r[2]=2.35*3 ±(3*0.5). r[] being the elements of the resulting list.
i'd start with 2.35*3=7.05, choose one element at random (e.g. 1.4), subtract the number 7.05-1.4=5.65, memoize the result.
repeat until the result of the subtrction is between 1.0 and 3.0.